Quant Test for SBI PO 2018 Prelim Exam Set – 60

Banya

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

 

Directions(1-5): Find the relation between x and y and choose a correct option in the following questions.

  1. I. 3x2 + 11x + 6 = 0
    II. 5y2 + 16y + 3 = 0

    x>=y
    x>y
    x=y or relation cannot be established.
    y>=x
    y>x
    Option D
    I. 3x2 + 11x + 6 = 0
    =>3x2 + 11x + 6 = 0
    =>3x2 + 9x + 2x + 6 = 0
    =>x = -3, -2/3
    II. 5y2 + 16y + 3 = 0
    =>5y2 + 16y + 3 = 0
    =>5y2 + 15y + y + 3 = 0
    => y = -1/5, -3
    y>=x

     

  2. I. x2 – 87x – 270 = 0
    II. 7y2 – 11y – 18 =0

    y>x
    y>=x
    x>y
    x=y or relation cannot be established.
    x>=y
    Option D
    I. x2 – 90x + 3x – 270 = 0
    => x = 90, -3
    II. 7y2 – 11y – 18 =0
    => 7y2 – 18y + 7y – 18 =0
    => y = 18/7, -1
    Relation cannot be established .

     

  3. I. x2− 19x + 84 = 0
    II. y2 − 25y + 156 = 0

    y>=x
    y>x
    x>=y
    x>y
    x=y or relation cannot be established.
    Option A
    I. x2 − 19x + 84 = 0
    =>x2 − 7x − 12x + 84 = 0
    => (x − 7)(x − 12) = 0
    => x = 7, 12
    II. y2 − 25y + 156 = 0
    => y2 − 13y − 12y + 156 = 0
    =>(y − 13)(y − 12) = 0
    ⇒ y = 13, 12
    x ≤ y

     

  4. I. 6x2 + 19x + 15 = 0
    II. 24y2 + 11y + 1 = 0

    x>y
    x>=y
    y>x
    x=y or relation cannot be established.
    y>=x
    Option C
    I. 6x2 + 19x + 15 = 0
    ⇒ (2x + 3)(3x + 5)
    ⇒ x = −3/2 , −5/3
    II. 24y2 + 11y + 1 = 0
    =>(3y + 1)(8y + 1) = 0
    => y = −1/8 , −1/3
    ⇒ x < y

     

  5. I. x2 – 208 = 333
    II. y2 + 47 – 371 =0

    x=y or relation cannot be established.
    y>=x
    y>x
    x>=y
    x>y
    Option A
    I. x2 – 208 = 333
    =>x= -21, 21
    II. y2 + 47 – 371 =0
    => y = -18,18
    Relation cannot be established.

     

  6. Out of a certain sum, one fourth is invested at 5%,one third is invested at 7% and the rest at 9%.If the simple interest for 2 years from all these investments amounts to Rs.880.find the original sum.
    5000
    8000
    4000
    6000
    7000
    Option D
    Rest part = 1 – [1 /4 + 1/ 3 ]= 5 /12
    Average rate per cent per annum on the total sum = [1 /4 × 5 ]+ [1/ 3 × 7] +[ 5/ 12 × 9] = 22/ 3 %
    𝑃 = (100 × 𝑆𝐼) /(𝑅 × 𝑇)
    = (100 × 880 × 3)/( 22 × 2)
    = 6000

     

  7. Ram and Rajesh were travelling to point Y from point X. Rajesh 3.5 hours to reach point Y while Ram took 4 hours to reach point Y. Ram increased his speed by 2km/hr. after every hour and initially the speed of Ram was 56.5 km/hr. Find the speed of the Rajesh if it is known that Rajesh travelled the entire distance at uniform speed.
    72 km/hr.
    68 km/hr.
    85 km/hr.
    70 km/hr.
    55 km/hr.
    Option B
    Distance between both the points
    = 56.5 + 58.5 + 60.5 + 62.5
    = 238 km
    Speed of Rajesh = 238/3.5
    = 68 km/hr.

     

  8. A man mixed 9 litres of water to certain quantity of milk such that the ratio of milk and water in the mixture becomes 8:3 resp. After that the quantity of milk in the mixture is increased by 25%. Find the resultant ratio of milk to water in the mixture.
    5:2
    11:9
    12:7
    10:3
    13:8
    Option D
    Let the initial quantity of milk that mixed be x litre.
    x/9 = 8/3
    => x = 24 litres
    Increased quantity of milk = 24 * 1.25
    = 30 litres
    Quantity of water = 9 litres
    Required ratio = 30:9 = 10:3

     

  9. The area of a square is 1444 square metre. The breadth of a rectangle is (1/4) th of the side of the square and the length of the rectangle is thrice the breadth. What is the difference between the area of the square and the area of the rectangle ?
    1713.05 sq. metre
    1002.25 sq. metre
    1133.21 sq. metre
    1003.05 sq. metre
    1173.25 sq. metre
    Option E
    Side of square = 1444 = 38 metre
    Breadth of rectangle = 1/4 × 38 = 19/2 metre
    Lenght of rectangle = 57/2 metre
    Required difference = 1444 – 19/2 × 57/2 = 1444 – 270.75
    = 1173.25 sq. metre

     

  10. A bag contains 12 white and 18 black balls. Two balls are drawn in succession without replacement. What is the probability that first is white and second is black?
    12/145
    11/147
    31/144
    36/145
    15/141
    Option D
    The probability that first ball is white: =12C1/30C1 =12/30 =2/5
    Since, the ball is not replaced; hence the number of balls left in bag is 29.
    Hence, the probability the second ball is black: = 18C1/29C1 =18/29
    Required probability, =(2/5)×(18/29) = 36/145

     


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